Minutes of the 15 Oct 2002 meeting
 ===================================
 (present: Tayfun, Tamara, and Michel)

- Tamara and Tayfun are continuing there study of the Athena code.
They have gone through the "Athena Cookbook" tutorial (now on our web
site) , and can now produce pedestals and standard ntuples.  It was
noted that care must be taken to use the right pedestal file: the code
runs just fine with a pedestal file corresponding to the wrong run
number.

- Tamara and Tayfun are looking forward to Margret's second chapter of
the "Athena Cookbook"!

- The LArDigitalFiltering package is robust, and allow for much
exploration of the timing features of the data.  Michel has produced
some preliminary synchronization of a weights file provided by Pavol,
and correspondence has been distributed to our group.  You are all
invited to look at the relevant file at
/afs/cern.ch/user/l/lefebvre/public/tb/dig
The plan is to soon make the weights and its synchronization public,
if it works...

- Michel discussed the usefulness of STL multimaps.  A hopefully
useful example can be found below.

#include <iostream>
#include <string>
#include <map>

main()
{
  multimap<int, string> m;
  typedef multimap<int, string>::value_type map_type;
  //
  // insert some names, keyed by their age
  m.insert(map_type(4, "bob"));
  m.insert(map_type(3, "joe"));
  m.insert(map_type(6, "jim"));
  m.insert(map_type(4, "dan"));
  m.insert(map_type(4, "rob"));
  m.insert(map_type(4, "tom"));
  m.insert(map_type(7, "sue"));
  m.insert(map_type(7, "tod"));
  //
  cout << "number of elements = " << m.size() << endl;
  //
  for (int key = 0; key < 10; key++) {
    cout << "number of elements with key = " << key 
	 << " is " << m.count(key) << endl;
    if (m.count(key) > 0) {
      for (multimap<int, string>::iterator it = m.find(key); 
	   it->first == key; ++it) {
	cout << it->second << endl;
      }
    }
  }
  
  return 0;
}


This code produces the following output:

number of elements = 8
number of elements with key = 0 is 0
number of elements with key = 1 is 0
number of elements with key = 2 is 0
number of elements with key = 3 is 1
joe
number of elements with key = 4 is 4
bob
dan
rob
tom
number of elements with key = 5 is 0
number of elements with key = 6 is 1
jim
number of elements with key = 7 is 2
sue
tod
number of elements with key = 8 is 0
number of elements with key = 9 is 0